Nuprl Lemma : pair_support_double_sum 4,23

nm:f:(nm), x1x2:ny1y2:m.
x1 = x2    y1 = y2  
 (x:ny:m(x = x1   & y = y1   (x = x2   & y = y2   f(x,y) = 0)
 sum(f(x,y) | x < ny < m) = f(x1,y1)+f(x2,y2
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Definitionsi  j < k, AB, False, P  Q, P & Q, x(s1,s2), A, Prop, {i..j}, t  T, , sum(f(x;y) | x < ny < m), x:AB(x), Dec(P), P  Q, sum(f(x) | x < k), xt(x), x(s), SQType(T), {T}
Lemmaspair support, empty support, sum wf, singleton support sum, decidable int equal, nat wf, int seg wf, not wf

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